Cutting Speed, Spindle Speed and Feed Rate

Surface speed and RPM, feed per tooth and per revolution, feed rate, metal removal rate and the unit conversions between metric and inch.

Cutting speed and spindle speed

The cutting speed (surface speed) Vc is how fast the cutting edge moves across the material: the speed of the tool rim in milling and drilling, or of the workpiece surface in turning. It depends on the material and on the tool, not on the machine. The spindle speed n (RPM) is what you set on the machine, and it follows from the surface speed and the diameter.

n = 1 000 × Vc ÷ (π × D)

Spindle speed falls as the tool gets bigger051015202506000120001800024000tool or work diameter (mm)spindle speed (rpm)spindle limit30 m/min100 m/min300 m/min
Spindle speed against diameter for three surface speeds: small tools need very high speeds.

Worked example: a 10 mm end mill in aluminum

  • Surface speed 100 m/min, diameter 10 mm: n = 1 000 × 100 ÷ (π × 10) = 3 183 rpm.
  • The same surface speed on a 20 mm cutter needs only 1 592 rpm, and on a 3 mm cutter 10 610 rpm: halving the diameter doubles the RPM.
  • A tool’s speed is limited by heat, not by RPM: a small tool must spin much faster to reach the same rim speed.

Metric and inch units

US shops quote surface speed in surface feet per minute (SFM) and diameters in inches. The formula becomes RPM = 12 × SFM ÷ (π × D) ≈ 3.82 × SFM ÷ D, with D in inches. The two systems are exactly equivalent (1 m = 3.28084 ft).

Surface speed (metric)Surface speed (inch)
30 m/min100 SFM
60 m/min195 SFM
100 m/min330 SFM
200 m/min655 SFM
300 m/min985 SFM
600 m/min1 970 SFM

Worked example: a 1/2 inch drill in mild steel

  • A high-speed steel drill in mild steel starts at about 100 SFM. RPM = 12 × 100 ÷ (π × 0.5) = 764 rpm (the shortcut 3.82 × 100 ÷ 0.5 = 764 agrees).
  • At a feed of 0.007 inch per revolution the feed rate is 764 × 0.007 = 5.3 in/min (136 mm/min).
  • A hole 1.0 inch deep takes about 11 s of cutting.

Feed: per tooth, per revolution, per minute

Feed is quoted three ways, and mixing them up is the commonest mistake.

NameSymbolUnitUsed for
Feed per tooth (chip load)fzmm/tooth, in/toothMilling: the chip thickness each tooth takes
Feed per revolutionfmm/rev, in/rev (IPR)Drilling, turning, tapping, reaming
Feed rateVfmm/min, in/min (IPM)What the controller is told to do

milling: Vf = n × z × fz    drilling, turning: Vf = n × f

Side viewTop viewSpindleapaxial depthFeedWorkpieceFeedaeradial depth (stepover)DClimb milling:teeth move withthe feed
Milling terms: axial depth a_p, radial depth a_e and the feed direction.

Worked example: milling feed rate

  • A 4-flute 10 mm end mill at 3 183 rpm and a chip load of 0.05 mm per tooth: Vf = 3 183 × 4 × 0.05 = 637 mm/min.
  • A two-flute tool at the same speed and chip load feeds at half that rate (318 mm/min): more flutes allow a faster feed for the same chip thickness, but leave less room for chips.
  • Doubling the RPM at the same chip load doubles the feed rate; the tool covers the work faster but wears faster too (see Tool Life, Wear and Cutting Economics).

Metal removal rate

The volume of material removed per minute, Q, measures how productive a cut is and what power it needs (see Cutting Force, Power and Torque).

milling: Q = ap × ae × Vf ÷ 1 000 (cm³/min)    turning: Q = Vc × ap × f (cm³/min)

Worked example: how much metal per minute

  • The mill above with a 8 mm depth and 5 mm stepover removes 8 × 5 × 637 ÷ 1 000 = 25 cm³/min.
  • To get more, increase the depth, the width or the feed: depth and width are cheap, speed is expensive, because speed shortens tool life far more than the others.
  • Doubling the removal rate by doubling the depth of cut costs about double the power; doubling it by doubling the cutting speed also costs double the power and cuts tool life sharply.

When the spindle cannot reach the speed

Small tools in soft materials want very high speeds, and many hobby spindles and routers stop at 10 000 to 24 000 rpm. When the ideal RPM is out of reach, run at the maximum and keep the chip load the same, so the feed rate falls in proportion. Never keep the feed rate and lower the RPM: the chip load would rise and the tool would break.

Worked example: a 3 mm cutter on an 18 000 rpm spindle

  • The ideal speed for 200 m/min is 21 221 rpm, beyond the spindle’s 18 000 rpm.
  • At 18 000 rpm the real surface speed is 170 m/min (85 % of the target): perfectly acceptable, as long as the material is not one that rubs and burns at low speed.
  • The ideal feed rate would be 21 221 × 2 × 0.02 = 849 mm/min; at the limit it is 18 000 × 2 × 0.02 = 720 mm/min. Keep the chip load and the feed follows the RPM.

RPM quick tables

Spindle speeds from the formula, in metric and inch. Read across from the diameter to the surface speed you want.

Diameter20 m/min30 m/min60 m/min100 m/min150 m/min250 m/min400 m/min
3 mm2 1203 1806 37010 61015 92026 53042 440
6 mm1 0601 5903 1805 3107 96013 26021 220
10 mm6379551 9103 1804 7707 96012 730
12 mm5317961 5902 6503 9806 63010 610
16 mm3985971 1901 9902 9804 9707 960
20 mm3184779551 5902 3903 9806 370
25 mm2553827641 2701 9103 1805 090
Diameter50 SFM100 SFM200 SFM300 SFM500 SFM800 SFM
1/8 in1 5303 0606 1109 17015 28024 450
1/4 in7641 5303 0604 5807 64012 220
3/8 in5091 0202 0403 0605 0908 150
1/2 in3827641 5302 2903 8206 110
3/4 in2555091 0201 5302 5504 070
1 in1913827641 1501 9103 060

Turning is the same idea

On a lathe the workpiece rotates, the diameter is the workpiece diameter, and the feed is per revolution. The details are in Turning, Threading and Surface Finish.

Worked example: turning a 50 mm bar

  • At 120 m/min on a 50 mm bar: n = 764 rpm. With a feed of 0.20 mm/rev the feed rate is 153 mm/min, so a 100 mm pass takes 39.3 s.
  • The removal rate at a 2 mm depth is 120 × 2 × 0.20 = 48 cm³/min.
  • As the diameter turns down, the RPM must rise to keep the same surface speed: constant surface speed (G96) does this automatically.

Troubleshooting

SymptomLikely causeTry
Tool is very hot or turns blueSurface speed too high, no coolantLower the RPM; use coolant or air; check the speed against the material data
Tool wears fast on the flankSpeed too high for the tool materialReduce the speed 20 %; use a harder coating or carbide
Edge rubs, glazes the surface, makes dust not chipsFeed too low for the speedRaise the feed until real chips form
Tool snaps or chipsFeed too high, or RPM too low for the feed rateReduce the feed per tooth; keep it with the RPM
Feed rate looks right but the cut is heavyMixed up feed per tooth and per revolutionRecalculate Vf = n × z × fz
Controller shows a different feed than the programUnits: mm/min against in/min, per rev against per minuteCheck the G-code units and the feed mode (G94, G95)

Related

FAQ

How do I convert SFM to RPM?

RPM = 3.82 × SFM ÷ diameter in inches. For 100 SFM and a 1/2 inch tool that is about 764 rpm.

What is the difference between chip load and feed rate?

Chip load (feed per tooth) is the thickness each tooth cuts; the feed rate is how fast the tool moves: feed rate = RPM × number of teeth × chip load.

Should I change speed or feed to fix a problem?

One at a time. Heat and fast flank wear point to speed; rubbing, dust and poor chips point to feed; breakage points to chip load or depth.

What do I do if my machine cannot reach the RPM?

Run at the maximum and keep the same chip load; the feed rate falls with the RPM.

References

  • Oberg, E., et al., Machinery’s Handbook (cutting speed and RPM formulas, SFM tables).
  • ISO 3002 (basic quantities in cutting and grinding) and ISO 3685.
  • Tool makers’ catalogs (Sandvik, Kennametal, Harvey, OSG) for speeds and feeds of specific tools.

Last reviewed: October 2026. Speeds and feeds are typical starting values: follow your tool maker’s data.