Diodes and LEDs

Rectifier, Schottky, Zener and TVS diodes, bridge rectifiers, and LED types with current limiting.

How a diode works

A diode lets current flow in one direction only, from anode to cathode (the arrow in the symbol points the way current flows; the bar marks the cathode, and the physical part has a stripe at that end). In the forward direction a diode conducts once the voltage across it reaches the forward voltage Vf, about 0.6–0.7 V for silicon. In reverse it blocks, until it reaches its breakdown voltage.

−6 V−5 V−4 V−3 V−2 V−1 V0 V+1 V+20 mA+10 mA−10 mASilicon≈ 0.7 VSchottky≈ 0.3 V5.1 V Zenerconducts in reverseReverse: almost no current until breakdownvoltage across the diode
Typical current-voltage curves: a silicon diode turns on at about 0.7 V, a Schottky at about 0.3 V, and a Zener conducts in reverse at its rated voltage.
  • Forward voltage drop means power is lost: P = Vf × I. A silicon diode carrying 1 A dissipates about 0.7 W.
  • Reverse voltage rating (VRRM) is the largest reverse voltage it will block. Choose one well above the highest voltage that can appear, including spikes.
  • A diode is not a resistor. The forward voltage is nearly constant, so the current is set by the rest of the circuit. Always limit the current with a resistor or a driver.

Types of diode

TypeExampleForward dropRating (typical)Use
Signal1N41480.6–0.7 V100 V, 200 mA, very fastLogic, clamping, small flyback
Rectifier1N4001–1N40070.7–1.0 V50–1 000 V, 1 A, slowMains and low-frequency rectification, flyback
Schottky1N5819, SS140.2–0.45 V20–100 V, 1–3 A, very fastSwitching supplies, reverse protection, low drop
Fast / ultrafastUF4007, MUR-series0.9–1.3 VTo 1 000 V, 50 ns recoveryHigh-frequency rectifiers, snubbers
ZenerBZX55 (2.4–75 V)reverse regulating0.5 W, 1 WReference, simple regulator, clamping
TVSSMBJ-seriesreverse clamping5–400 V, 600 W pulsesSurge and ESD protection
LEDmany1.8–3.4 V10–20 mA (small)Light; see below
PhotodiodeBPW34—Reverse-biasedLight sensing, receivers

A Schottky diode has a metal-semiconductor junction. It drops much less voltage and switches faster than a silicon diode, but leaks more in reverse and has a lower voltage rating.

Rectifiers and power supplies

Rectifying turns AC into pulsating DC. A half-wave rectifier is one diode and passes one half-cycle. A full-wave bridge uses four diodes so that every half-cycle goes the same way through the load; the current always passes through two diodes, so the loss is about 1.4 V. A filter capacitor then fills the gaps between the peaks.

D1D2D3D4+filtercapacitorloadDC +DC −AC inEither half-cycle passes through two diodes, so about 1.4 V is lost. Ripple ≈ I ÷ (2 × f × C).
A bridge rectifier with a filter capacitor and load. On each half-cycle current flows through one pair of diodes.

VDC ≈ VRMS × 1.414 − 1.4 V    ripple ΔV ≈ I ÷ (2 × f × C) (full-wave)

Worked example: a 12 V AC secondary into a bridge

  • Peak voltage: 12 × 1.414 = 17.0 V. After two diode drops: 17.0 − 1.4 = 15.6 V DC at the peaks.
  • For a 0.5 A load at 60 Hz, a ripple of 1 V needs C = I ÷ (2 × f × ΔV) = 0.5 ÷ (2 × 60 × 1) = 4 167 µF. With a standard 4 700 µF capacitor, the ripple is 0.5 ÷ (120 × 0.0047) = 0.89 V.
  • The minimum voltage (peak minus ripple) must still stay above the regulator’s required input, or the output will dip every cycle.
  • Pick diodes rated for at least 2× the peak reverse voltage and with a current rating above the average load current, and remember that the charging pulses are much larger than the average current.

The result is a rough DC supply; follow it with a regulator (see Batteries and Power Supplies). Mains-powered circuits can kill: use a ready-made, certified supply unless you are qualified.

Zener diodes and TVS

A Zener diode is designed to be used in reverse. Above its rated voltage it conducts and holds the voltage nearly constant, which makes a simple reference or a clamp. A TVS (transient voltage suppressor) is a Zener-like part built to absorb large short pulses: put one across a supply or a data line to clamp surges and static.

Rseries = (Vin − VZ) ÷ (IZ + Iload)

Worked example: a 5.1 V Zener from 12 V

  • The load takes 10 mA, and the Zener needs at least 5 mA to regulate: R = (12 − 5.1) ÷ (0.005 + 0.010) = 460 Ω. The nearest standard value is 470 Ω.
  • Current in the resistor: 6.9 ÷ 470 = 14.7 mA, of which 4.7 mA flows in the Zener.
  • Power: resistor 0.10 W (a ¼ W part is fine), Zener 23.9 mW.
  • If the load is removed, the Zener carries all 14.7 mA, so it must be rated for 5.1 × 14.7 mA = 74.9 mW.
  • A Zener regulator wastes power and has a poor output resistance. It suits references and tiny loads; for anything else use a regulator IC.

LEDs

A light-emitting diode gives off light when current flows forward. The color sets the forward voltage; the brightness follows the current, not the voltage. The longer lead is the anode (+), and the flat side of the lens marks the cathode.

ColorForward voltage (typical)Notes
Infrared1.2–1.6 VRemote controls, sensors
Red, orange, yellow1.8–2.2 VLowest forward voltage
Green2.0–3.3 VVaries widely with type
Blue, white, UV2.8–3.4 VLittle headroom on a 3.3 V supply
RGBper colorThree LEDs in one package; common anode or common cathode
  • Maximum current for a 5 mm indicator LED is about 20 mA. For normal use, 5–10 mA is plenty bright, and it lasts longer.
  • Brightness is not proportional to current. Perceived brightness is roughly logarithmic, so halving the current looks only slightly dimmer.
  • Power LEDs (1 W and up) need a heat sink and a constant-current driver, not a resistor.

Choosing the LED resistor

R = (Vsupply − Vf) ÷ ILED

The table gives the calculated resistance for 10 mA, the nearest standard (E24) value, and the actual current that results.

LED (Vf)3.3 V supply5 V supply12 V supply
Red (2.0 V)130 Ω → 130 Ω (10.0 mA)300 Ω → 300 Ω (10.0 mA)1 kΩ → 1 kΩ (10.0 mA)
Green (2.2 V)110 Ω → 110 Ω (10.0 mA)280 Ω → 270 Ω (10.4 mA)980 Ω → 1 kΩ (9.8 mA)
White / blue (3.2 V)not enough headroom180 Ω → 180 Ω (10.0 mA)880 Ω → 910 Ω (9.7 mA)
  • Blue and white on 3.3 V is fragile. With Vf = 3.0 V the resistor is only 30 Ω; because Vf varies from part to part (2.8–3.2 V), the current could be anywhere from 3.3 to 16.7 mA. Use a higher supply or a constant-current driver.
  • Several LEDs in series need the supply to exceed the sum of the forward voltages, with one resistor: three red LEDs on 12 V need R = (12 − 6) ÷ 0.010 = 600 Ω → 620 Ω.
  • LEDs in parallel should each have their own resistor, because they do not share current evenly.
  • Power in the resistor: P = (Vsupply − Vf) × I. For 12 V and a red LED at 10 mA, that is 0.1 W, so a ¼ W part is enough.

Driving LEDs well

  • From a microcontroller pin: the pin supplies only 10–20 mA, so use one LED per pin through a resistor. For more, switch with a transistor (see Transistors).
  • Dimming: use PWM (switch on and off fast, at least 200 Hz so it does not flicker). The color stays true, unlike lowering the current.
  • LED strips and modules usually have the resistors built in and run at a fixed 5 V, 12 V or 24 V. Use a supply rated 20 % above the strip’s total current and check the wire gauge for long runs.
  • Reverse polarity damages some LEDs: they tolerate only about 5 V in reverse. Mind the orientation.
  • Addressable LEDs (WS2812, “NeoPixel”) contain a driver chip in each package, are chained on one data line and need a 5 V supply with decoupling and a small series resistor on the data line.

Related

FAQ

Can I connect an LED straight to a battery?

Not safely. The LED’s current rises steeply once it turns on, so with no resistor it draws as much as the battery can give and burns out. A coin cell (CR2032) has enough internal resistance to limit the current, which is why some LED throwies work, but it is not good practice.

Why use a Schottky diode?

It drops less voltage than silicon (0.3 V against 0.7 V), so it wastes less power and leaves more voltage for the load, and it switches faster. It is the usual choice for reverse-polarity protection of low voltages and for the diode in a switching regulator.

What is the difference between a Zener and a TVS?

Both clamp voltage. A Zener is built to hold a voltage steadily and carry a modest current; a TVS is built to absorb a short, large energy pulse such as a static discharge or a motor spike. Use a TVS for protection and a Zener for reference.

Why does my LED glow faintly when it should be off?

A tiny leakage current, from a pull-up, a transistor’s off-state current or a long wire coupling mains noise, is enough to give a faint glow. Add a resistor in parallel with the LED, or a bleeder at the switch.

How do I tell which side of a diode is the cathode?

Look for the stripe on a rectifier or signal diode; on an LED, the flat side of the lens or the shorter lead is the cathode. Or use the diode-test range of a multimeter: it reads about 0.6 V with the red lead on the anode.

References

  • Horowitz, P. and Hill, W., The Art of Electronics, 3rd ed., Cambridge University Press: chapter 1 (diodes) and chapter 2.
  • Manufacturer datasheets for 1N4148, 1N4001–1N4007, 1N5819, BZX55 and SMBJ series (for example Vishay, onsemi, Diodes Inc.).
  • LED manufacturers’ datasheets (for example Kingbright, Lite-On, Cree): forward voltage and current ratings by color.
  • IEC 60063, preferred number series (E24) for resistor selection.

Last reviewed: October 2026. Values are typical: check the datasheets of the parts you use. Mains-powered rectifiers can kill: use certified supplies unless you are qualified.